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(F)=15F^2-2
We move all terms to the left:
(F)-(15F^2-2)=0
We get rid of parentheses
-15F^2+F+2=0
a = -15; b = 1; c = +2;
Δ = b2-4ac
Δ = 12-4·(-15)·2
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-11}{2*-15}=\frac{-12}{-30} =2/5 $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+11}{2*-15}=\frac{10}{-30} =-1/3 $
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